WebA body of mass m is projected vertically upward with an initial velocity v0 in a medium offering a resistance k v , where k is a constant. Assume that the gravitational attraction of the earth is constant.(a) Find the velocity v(t) of the body at any time. (b) Use the result of part (a) to calculate the limit of v(t)ask→0—that is, as the ... WebA body thrown up with some initial velocity reaches a maximum height of 50m. Another body with double the mass thrown up with double the initial velocity will reach a maximum height of : Medium. View solution. >. From an elevated point P, a stone is projected vertically upwards. When it reaches a distance d below P, its velocity is doubled.
A body is projected vertically upwards from the surface of …
WebApr 9, 2024 · Solution For A body is projected vertically upward under gravity only for time of flight 10 s. Distance travelled by the body in 3rd second is equal . The world’s only live instant tutoring platform. Become a tutor About us Student login Tutor login. Login. Student Tutor. Filo instant Ask button for chrome browser. ... WebJun 21, 2024 · A body is thrown vertically upwards with a velocity of 78.4 m s-1. Find how high it will rise and how much time it will take to return to its point of projection. g = 9.8 ms-2. Given: Velocity of projection = u = +78.4 m s -1, acceleration due to gravity = g = – 9.8 m s -2. To Find: Height reached = h =?, Time of flight = T =? Solution: people seem strange when you\u0027re a stranger
What expression can be derived for the maximum height reached …
WebAnswer (1 of 3): You can plug initial velocity information into an equation and easily find the answer. I like to think of ways that help a student understand why. Just plug it in: Vf = Vi … WebFeb 8, 2008 · A body of mass 7 kg is projected vertically upward with an initial velocity 32 meters per second. The gravitational constant is g = 9.8 m/s^2. The air resistance is equal to k*abs (v) where k is a constant. Find a formula for the velocity at any time ( in terms of k): v (t) = ? going up dv/dt = - 9.8 - kv going down dv/dt = 9.8 - kv Now continue... WebJun 28, 2024 · When a body is projected vertically upwards with a velocity 10 m/s, its speed after 1 second is (g =10m/s₂) Options- (A) 20 m/s (B) zero (C) 10 m/s (D) 15 m/s Answer- v = final velocity u = initial velocity g = gravitational acceleration s = displacement. people seeing ghosts